Mahogany Ebony
Genetics recombination question?
In Drosophila, mahogany and ebony are recessive mutations. The genes for mahogany eyes and ebony body are 25 map units apart on a Drosophila autosome. A true breeding mahogany female was mated to a true breeding ebony male, and phenotypically wild-type F1 females were test crossed to mahogany, ebony males. Of 1000 offspring, what would be the expected phenotypes and in what numbers would they be expected?
m: mahogani eyes; M: normal eyes (wild type)
e: ebony body; E: normal bony (wild type)
P: female mahogany (mE/mE) >< male ebony (Me/Me)
Gamete: (mE) >< (Me)
F1: mE/Me (wild types)
Testcross: mE/Me >< me/me
Female gametes (25 mu):
mE = 0.375
me = 0.125
ME = 0.125
Me = 0.375
Male gamete: me = 100%
Progeny:
mE/me (mahogany) = 0.375 x 1000 = 375
me/me (mahogany, ebony) = 0.125 x 1000 = 125
ME/me (wild types) = 0.125 x 1000 = 125
Me/me (ebony) = 0.375 x 1000 = 375